What is the answer to 8^{2x}=3^{2x-1} ?

The answer to 8^{2x}=3^{2x-1} is x=-(ln(3))/(2(3ln(2)-ln(3)))

Solve for x: 8^{2x}=3^{2x-1}

The solution is x=-(ln(3))/(2(3ln(2)-ln(3)))

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8^{2 x} = 3^{2 x - 1}

x = - \frac{ln ( 3 )}{2 ( 3 ln ( 2 ) - ln ( 3 ) )}

Decimal Notation

x = - 0.56004 \dots

Solution steps

8^{2 x} = 3^{2 x - 1}

Apply exponent rules

2 x ln (8) = (2 x - 1) ln (3)

Solve

2 x ln (8) = (2 x - 1) ln (3) : x = - \frac{ln ( 3 )}{2 ( 3 ln ( 2 ) - ln ( 3 ) )}

x = - \frac{ln ( 3 )}{2 ( 3 ln ( 2 ) - ln ( 3 ) )}

2 e^{3 x - 7} - 6 = 3

1 0^{x + 7} = 4^{2 x}

2^{2 x - 1} = 323.2

2^{5} \cdot 2^{x} = 128

2^{x} = 47

What is the answer to 8^{2x}=3^{2x-1} ?
The answer to 8^{2x}=3^{2x-1} is x=-(ln(3))/(2(3ln(2)-ln(3)))
Solve for x: 8^{2x}=3^{2x-1}
The solution is x=-(ln(3))/(2(3ln(2)-ln(3)))