What is the answer to 2^x=\sqrt[3]{4} ?

The answer to 2^x=\sqrt[3]{4} is x= 2/3

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2^x=\sqrt[3]{4}

x = \frac{2}{3}

Solution steps

Apply exponent rules

x = \frac{2}{3}

2^{x} = 73

(0.5)^{x} = \frac{1}{16}

3^{\frac{x}{14}} = \frac{1}{10}

4^{(3 x - 7)} = 16

1 6^{n - 7} = 19