What is the answer to 2^{2x+4}=3^{x-24} ?

The answer to 2^{2x+4}=3^{x-24} is x=(-24ln(3)-4ln(2))/(2ln(2)-ln(3))

Solve for x: 2^{2x+4}=3^{x-24}

The solution is x=(-24ln(3)-4ln(2))/(2ln(2)-ln(3))

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2^{2 x + 4} = 3^{x - 24}

x = \frac{- 24 ln ( 3 ) - 4 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

Solution steps

2^{2 x + 4} = 3^{x - 24}

Apply exponent rules

(2 x + 4) ln (2) = (x - 24) ln (3)

Solve

(2 x + 4) ln (2) = (x - 24) ln (3) : x = \frac{- 24 ln ( 3 ) - 4 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{- 24 ln ( 3 ) - 4 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

2^{2 - x} = 5^{x + 1}

2^{n} = 100

8 \cdot 2^{x + 1} = 2^{2 x}

\frac{1}{6 ^{x - 1}} = 216

5^{2 x} = 8

What is the answer to 2^{2x+4}=3^{x-24} ?
The answer to 2^{2x+4}=3^{x-24} is x=(-24ln(3)-4ln(2))/(2ln(2)-ln(3))
Solve for x: 2^{2x+4}=3^{x-24}
The solution is x=(-24ln(3)-4ln(2))/(2ln(2)-ln(3))