What is the answer to 3^{2x+1}+8(3^x)-3=0 ?

The answer to 3^{2x+1}+8(3^x)-3=0 is x=-1

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3^{2x+1}+8(3^x)-3=0

3^{2 x + 1} + 8 (3^{x}) - 3 = 0

x = - 1

Solution steps

3^{2 x + 1} + 8 (3^{x}) - 3 = 0

Apply exponent rules

(3^{x})^{2} \cdot 3^{1} + 8 \cdot 3^{x} - 3 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{1} + 8 u - 3 = 0

Solve

u^{2} \cdot 3^{1} + 8 u - 3 = 0 : u = \frac{1}{3}, u = - 3

u = \frac{1}{3}, u = - 3

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = \frac{1}{3} : x = - 1

Solve

3^{x} = - 3 :

No Solution for

x \in R

x = - 1

e^{2 l n (b)} = 256

\frac{1025}{8 + e ^{4 x}} = 5

4^{x} = 9 (5^{x})

x, y = (x + F) e^{- x}

3.4 e^{2 - 2 n} - 9 = - 4

What is the answer to 3^{2x+1}+8(3^x)-3=0 ?
The answer to 3^{2x+1}+8(3^x)-3=0 is x=-1
Solve for x: 3^{2x+1}+8(3^x)-3=0
The solution is x=-1