What is the answer to 62*2^{5x}=27 ?

The answer to 62*2^{5x}=27 is x=(ln(27/62))/(5ln(2))

Solve for x: 62*2^{5x}=27

The solution is x=(ln(27/62))/(5ln(2))

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62 \cdot 2^{5 x} = 27

x = \frac{ln ( \frac{27}{62} )}{5 ln ( 2 )}

Decimal Notation

x = - 0.23986 \dots

Solution steps

62 \cdot 2^{5 x} = 27

Divide both sides by

62

2^{5 x} = \frac{27}{62}

Apply exponent rules

5 x ln (2) = ln (\frac{27}{62})

Solve

5 x ln (2) = ln (\frac{27}{62}) : x = \frac{ln ( \frac{27}{62} )}{5 ln ( 2 )}

x = \frac{ln ( \frac{27}{62} )}{5 ln ( 2 )}

3^{x} = 6561

8^{x} = 12143

2^{x - 1} = 2^{x} - 8

2^{(x^{2})} = 1 6^{x - 1}

3^{x} = 9^{x + 1}

What is the answer to 62*2^{5x}=27 ?
The answer to 62*2^{5x}=27 is x=(ln(27/62))/(5ln(2))
Solve for x: 62*2^{5x}=27
The solution is x=(ln(27/62))/(5ln(2))