What is the answer to 8^{4x-3}=(1/16)^{x+1} ?

The answer to 8^{4x-3}=(1/16)^{x+1} is x= 5/16

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8^{4x-3}=(1/16)^{x+1}

8^{4 x - 3} = (\frac{1}{16})^{x + 1}

x = \frac{5}{16}

Solution steps

8^{4 x - 3} = (\frac{1}{16})^{x + 1}

Apply exponent rules

3 (4 x - 3) = - 4 (x + 1)

Solve

3 (4 x - 3) = - 4 (x + 1) : x = \frac{5}{16}

x = \frac{5}{16}

4 e^{- x} = 3 e^{x} + 4

1 0^{x} = (1 0^{- 14}) (1 0^{2})

6 (3^{2 x}) = 2^{x + 1}

9^{2 x - 1} = 27

ln (3) = e^{x}

What is the answer to 8^{4x-3}=(1/16)^{x+1} ?
The answer to 8^{4x-3}=(1/16)^{x+1} is x= 5/16
Solve for x: 8^{4x-3}=(1/16)^{x+1}
The solution is x= 5/16