What is the answer to (2^x-3)(2^x-4)=0 ?

The answer to (2^x-3)(2^x-4)=0 is x=(ln(3))/(ln(2)),x=2

Solve for x: (2^x-3)(2^x-4)=0

The solution is x=(ln(3))/(ln(2)),x=2

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(2^{x} - 3) (2^{x} - 4) = 0

x = \frac{ln ( 3 )}{ln ( 2 )}, x = 2

Solution steps

(2^{x} - 3) (2^{x} - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{x} - 3 = 0 or 2^{x} - 4 = 0

Solve

2^{x} - 3 = 0 : x = \frac{ln ( 3 )}{ln ( 2 )}

Solve

2^{x} - 4 = 0 : x = 2

x = \frac{ln ( 3 )}{ln ( 2 )}, x = 2

9^{- x + 15} = 2 7^{x}

3^{5 x} = 9

312 5^{x} = e

2 5^{2 x - 3} = 12 5^{x + 4}

8^{l o g_{4} (x)} = 64

What is the answer to (2^x-3)(2^x-4)=0 ?
The answer to (2^x-3)(2^x-4)=0 is x=(ln(3))/(ln(2)),x=2
Solve for x: (2^x-3)(2^x-4)=0
The solution is x=(ln(3))/(ln(2)),x=2