What is the answer to (6^x)/(3^x)=5 ?

The answer to (6^x)/(3^x)=5 is x=(ln(5))/(ln(2))

Solve for x: (6^x)/(3^x)=5

The solution is x=(ln(5))/(ln(2))

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\frac{6 ^{x}}{3 ^{x}} = 5

x = \frac{ln ( 5 )}{ln ( 2 )}

Solution steps

\frac{6 ^{x}}{3 ^{x}} = 5

Apply exponent rules

(lo g_{3} (6) x - x) ln (3) = ln (5)

Solve

(lo g_{3} (6) x - x) ln (3) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 2 )}

Verify Solutions:

x = \frac{ln ( 5 )}{ln ( 2 )}

True

The solution is

x = \frac{ln ( 5 )}{ln ( 2 )}

3 x - e^{x - 2} - 4 = 0

(3^{x + 1}) (4^{x + 2}) = 5^{2 x - 1}

2 e^{x} = 7 e^{x} - 3

\frac{1}{64} = 2^{x}

12 5^{x - 1} = 2 5^{x}

What is the answer to (6^x)/(3^x)=5 ?
The answer to (6^x)/(3^x)=5 is x=(ln(5))/(ln(2))
Solve for x: (6^x)/(3^x)=5
The solution is x=(ln(5))/(ln(2))