What is the answer to 3^{2x-x^2}=5^{4x^2-3x} ?

The answer to 3^{2x-x^2}=5^{4x^2-3x} is x=0,x=(ln(1125))/(ln(1875))

Solve for x: 3^{2x-x^2}=5^{4x^2-3x}

The solution is x=0,x=(ln(1125))/(ln(1875))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2 x - x^{2}} = 5^{4 x^{2} - 3 x}

x = 0, x = \frac{ln ( 1125 )}{ln ( 1875 )}

Decimal Notation

x = 0, x = 0.93221 \dots

Solution steps

3^{2 x - x^{2}} = 5^{4 x^{2} - 3 x}

Apply exponent rules

(2 x - x^{2}) ln (3) = (4 x^{2} - 3 x) ln (5)

Solve

(2 x - x^{2}) ln (3) = (4 x^{2} - 3 x) ln (5) : x = 0, x = \frac{ln ( 1125 )}{ln ( 1875 )}

x = 0, x = \frac{ln ( 1125 )}{ln ( 1875 )}

8^{x} = 3

e^{- x} = 0.1

1 0^{14} = (1 0^{11}) (1 0^{x})

3^{(- 3 x - 8)} = 3^{(- 6 x + 3)}

x 4 \cdot 3^{3 x + 2} + 3^{3 x + 3} = 7

What is the answer to 3^{2x-x^2}=5^{4x^2-3x} ?
The answer to 3^{2x-x^2}=5^{4x^2-3x} is x=0,x=(ln(1125))/(ln(1875))
Solve for x: 3^{2x-x^2}=5^{4x^2-3x}
The solution is x=0,x=(ln(1125))/(ln(1875))