What is the answer to 2^{x+3}+63= 8/(2^x) ?

The answer to 2^{x+3}+63= 8/(2^x) is x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x+3}+63= 8/(2^x)

2^{x + 3} + 63 = \frac{8}{2 ^{x}}

x = - 3

Solution steps

2^{x + 3} + 63 = \frac{8}{2 ^{x}}

Apply exponent rules

2^{x} \cdot 2^{3} + 63 = 8 (2^{x})^{- 1}

Rewrite the equation with

2^{x} = u

u \cdot 2^{3} + 63 = 8 (u)^{- 1}

Solve

u \cdot 2^{3} + 63 = 8 u^{- 1} : u = \frac{1}{8}, u = - 8

u = \frac{1}{8}, u = - 8

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = \frac{1}{8} : x = - 3

Solve

2^{x} = - 8 :

No Solution for

x \in R

x = - 3

Verify Solutions:

x = - 3

True

The solution is

x = - 3

3^{n} = 33

8^{\frac{7 x + 1}{x}} = 0.25

1. 1^{x} = 100

1. 2^{x} = (0.5)^{- x}

x, e^{- 1} = e^{x y}

What is the answer to 2^{x+3}+63= 8/(2^x) ?
The answer to 2^{x+3}+63= 8/(2^x) is x=-3
Solve for x: 2^{x+3}+63= 8/(2^x)
The solution is x=-3