What is the answer to 3^{2x-1}=7 ?

The answer to 3^{2x-1}=7 is x=(ln(21))/(2ln(3))

Solve for x: 3^{2x-1}=7

The solution is x=(ln(21))/(2ln(3))

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3^{2 x - 1} = 7

x = \frac{ln ( 21 )}{2 ln ( 3 )}

Decimal Notation

x = 1.38562 \dots

Solution steps

3^{2 x - 1} = 7

Apply exponent rules

(2 x - 1) ln (3) = ln (7)

Solve

(2 x - 1) ln (3) = ln (7) : x = \frac{ln ( 21 )}{2 ln ( 3 )}

x = \frac{ln ( 21 )}{2 ln ( 3 )}

12 5^{x + 2} = 1

5^{2 x - 3} = 9

1 0^{3 y} = 21

e^{2 x - 2} = 4

2^{2 x} - 6 \cdot 2^{x} - 16 = 0

What is the answer to 3^{2x-1}=7 ?
The answer to 3^{2x-1}=7 is x=(ln(21))/(2ln(3))
Solve for x: 3^{2x-1}=7
The solution is x=(ln(21))/(2ln(3))