What is the answer to (27^39^{-2})/(81)=3^x ?

The answer to (27^39^{-2})/(81)=3^x is x=1

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(27^39^{-2})/(81)=3^x

\frac{2 7 ^{3} 9 ^{- 2}}{81} = 3^{x}

x = 1

Solution steps

\frac{2 7 ^{3} \cdot 9 ^{- 2}}{81} = 3^{x}

Apply exponent rules

ln (\frac{3 ^{3 \cdot 3} \cdot 3 ^{2 (- 2)}}{81}) = x ln (3)

Solve

ln (\frac{3 ^{3 \cdot 3} \cdot 3 ^{2 (- 2)}}{81}) = x ln (3) : x = 1

x = 1

3^{2 x + 1} - 4 \cdot 3^{x} + 1 = 0

8^{2 x + 1} = 12 8^{x - 3}

1.0 3^{x} = 2

4^{x} + 4^{2} = 4^{x + 2}

4^{x} + 48 = 19 \cdot 2^{x}

What is the answer to (27^39^{-2})/(81)=3^x ?
The answer to (27^39^{-2})/(81)=3^x is x=1
Solve for x: (27^39^{-2})/(81)=3^x
The solution is x=1