What is the answer to 14*4^{x-1}=2*7^{x-1} ?

The answer to 14*4^{x-1}=2*7^{x-1} is x=(2ln(7)-2ln(2))/(ln(7)-2ln(2))

Solve for x: 14*4^{x-1}=2*7^{x-1}

The solution is x=(2ln(7)-2ln(2))/(ln(7)-2ln(2))

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14 \cdot 4^{x - 1} = 2 \cdot 7^{x - 1}

x = \frac{2 ln ( 7 ) - 2 ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

Decimal Notation

x = 4.47722 \dots

Solution steps

14 \cdot 4^{x - 1} = 2 \cdot 7^{x - 1}

Apply exponent rules

ln (14) + (x - 1) ln (4) = ln (2) + (x - 1) ln (7)

Solve

ln (14) + (x - 1) ln (4) = ln (2) + (x - 1) ln (7) : x = \frac{2 ln ( 7 ) - 2 ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

x = \frac{2 ln ( 7 ) - 2 ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

4^{x} - 2^{x} = 0

4^{x} - 2^{x} = 6

x, y = 4^{x} y

x, e^{x} = 2^{y}

23 = 520 (0.5)^{\frac{x}{7}}

What is the answer to 14*4^{x-1}=2*7^{x-1} ?
The answer to 14*4^{x-1}=2*7^{x-1} is x=(2ln(7)-2ln(2))/(ln(7)-2ln(2))
Solve for x: 14*4^{x-1}=2*7^{x-1}
The solution is x=(2ln(7)-2ln(2))/(ln(7)-2ln(2))