What is the answer to 77=23^x ?

The answer to 77=23^x is x=(ln(77))/(ln(23))

The solution is x=(ln(77))/(ln(23))

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77=23^x

77 = 2 3^{x}

x = \frac{ln ( 77 )}{ln ( 23 )}

Solution steps

77 = 2 3^{x}

Apply exponent rules

ln (77) = x ln (23)

Solve

ln (77) = x ln (23) : x = \frac{ln ( 77 )}{ln ( 23 )}

x = \frac{ln ( 77 )}{ln ( 23 )}

3^{2 x} + 2 \cdot 3^{x} + 1 = 0

x, F x + e^{- x} F_{y} = 0

e^{- x} - x e^{- x} = 0

1 1^{x} = 1331

e^{3 x - 1} = 3^{x}