What is the answer to 2^x-2^{-x}=5-5*2^{-x} ?

The answer to 2^x-2^{-x}=5-5*2^{-x} is x=2,x=0

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2^x-2^{-x}=5-5*2^{-x}

2^{x} - 2^{- x} = 5 - 5 \cdot 2^{- x}

x = 2, x = 0

Solution steps

2^{x} - 2^{- x} = 5 - 5 \cdot 2^{- x}

Apply exponent rules

2^{x} - (2^{x})^{- 1} = 5 - 5 (2^{x})^{- 1}

Rewrite the equation with

2^{x} = u

u - (u)^{- 1} = 5 - 5 (u)^{- 1}

Solve

u - u^{- 1} = 5 - 5 u^{- 1} : u = 4, u = 1

u = 4, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 4 : x = 2

Solve

2^{x} = 1 : x = 0

x = 2, x = 0

3^{5 x} \cdot 9^{x^{2}} = 27

2700 = 860 (1.015)^{0.61 x} + 1000

1 0^{3 + x} = 810

x, (1 - y) y^{1} + 2 y = e^{x}

5^{y} = 25

What is the answer to 2^x-2^{-x}=5-5*2^{-x} ?
The answer to 2^x-2^{-x}=5-5*2^{-x} is x=2,x=0
Solve for x: 2^x-2^{-x}=5-5*2^{-x}
The solution is x=2,x=0