What is the answer to solvefor x,8^y=4^{2x+1} ?

The answer to solvefor x,8^y=4^{2x+1} is x=(3y-2)/4

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solvefor x,8^y=4^{2x+1}

solve for

x, 8^{y} = 4^{2 x + 1}

x = \frac{3 y - 2}{4}

Solution steps

8^{y} = 4^{2 x + 1}

Apply exponent rules

3 y = 2 (2 x + 1)

Solve

3 y = 2 (2 x + 1) : x = \frac{3 y - 2}{4}

x = \frac{3 y - 2}{4}

e^{4 x} + 2 e^{2 x} - 8 = 0

k, k (x) = x^{4} e^{3 x}

(1 6^{32})^{x - 2} = 2^{2^{x + 2}}

x, F x + e^{- x} F y = 0

4^{2 x} = 3 2^{x - 2}

What is the answer to solvefor x,8^y=4^{2x+1} ?
The answer to solvefor x,8^y=4^{2x+1} is x=(3y-2)/4