What is the answer to 78*1.055^t=110 ?

The answer to 78*1.055^t=110 is t=(ln(55/39))/(ln(1.055))

Solve for t: 78*1.055^t=110

The solution is t=(ln(55/39))/(ln(1.055))

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78 \cdot 1.05 5^{t} = 110

t = \frac{ln ( \frac{55}{39} )}{ln ( 1.055 )}

Solution steps

78 \cdot 1.05 5^{t} = 110

Divide both sides by

78

1.05 5^{t} = \frac{55}{39}

Apply exponent rules

t ln (1.055) = ln (\frac{55}{39})

Solve

t ln (1.055) = ln (\frac{55}{39}) : t = \frac{ln ( \frac{55}{39} )}{ln ( 1.055 )}

t = \frac{ln ( \frac{55}{39} )}{ln ( 1.055 )}

g (p) = 4^{x}, x = \frac{3}{2}

3 (2^{x}) = 48

2 7^{x} = (\frac{1}{3})^{2 x}

0. 6^{x} = 2^{x^{2}}

9^{x - 2} = (\frac{1}{3})^{3 x - 1}

What is the answer to 78*1.055^t=110 ?
The answer to 78*1.055^t=110 is t=(ln(55/39))/(ln(1.055))
Solve for t: 78*1.055^t=110
The solution is t=(ln(55/39))/(ln(1.055))