What is the answer to 2*7^{-6x}=36 ?

The answer to 2*7^{-6x}=36 is x=-(ln(18))/(6ln(7))

Solve for x: 2*7^{-6x}=36

The solution is x=-(ln(18))/(6ln(7))

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2 \cdot 7^{- 6 x} = 36

x = - \frac{ln ( 18 )}{6 ln ( 7 )}

Decimal Notation

x = - 0.24755 \dots

Solution steps

2 \cdot 7^{- 6 x} = 36

Divide both sides by

2

7^{- 6 x} = 18

Apply exponent rules

- 6 x ln (7) = ln (18)

Solve

- 6 x ln (7) = ln (18) : x = - \frac{ln ( 18 )}{6 ln ( 7 )}

x = - \frac{ln ( 18 )}{6 ln ( 7 )}

e^{2 x} - 1 = 0

a, e^{2 ab} = e^{a}

6^{x} = 0.2 5^{2 x - 1}

4 (2.5)^{2 x} = 4

\frac{400}{1 + e ^{- x}} = 350

What is the answer to 2*7^{-6x}=36 ?
The answer to 2*7^{-6x}=36 is x=-(ln(18))/(6ln(7))
Solve for x: 2*7^{-6x}=36
The solution is x=-(ln(18))/(6ln(7))