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Popular >

solvefor x,y^2=2^x

Solution

solve for

x, y^{2} = 2^{x}

Solution

x = \frac{2 ln ( y )}{ln ( 2 )}

Solution steps

y^{2} = 2^{x}

Apply exponent rules

2 ln (y) = x ln (2)

Solve

2 ln (y) = x ln (2) : x = \frac{2 ln ( y )}{ln ( 2 )}

x = \frac{2 ln ( y )}{ln ( 2 )}

Popular Examples

(0.25)^{(x-3)}=2^{(x+8)}

(0.25)^{(x - 3)} = 2^{(x + 8)}

solvefor y,7^{2y}=3^4 solve for

y, 7^{2 y} = 3^{4}

2^{20x+10}=32^{4x+2}

2^{20 x + 10} = 3 2^{4 x + 2}

e^{2 l n (x)} = 196

2^{x+1}+2^{2x}=288

2^{x + 1} + 2^{2 x} = 288

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,y^2=2^x ?
The answer to solvefor x,y^2=2^x is x=(2ln(y))/(ln(2))