What is the answer to 3(2^{x+3})=192(3^{x-3}) ?

The answer to 3(2^{x+3})=192(3^{x-3}) is x=-(ln(8/27))/(ln(3)-ln(2))

Solve for x: 3(2^{x+3})=192(3^{x-3})

The solution is x=-(ln(8/27))/(ln(3)-ln(2))

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3 (2^{x + 3}) = 192 (3^{x - 3})

x = - \frac{ln ( \frac{8}{27} )}{ln ( 3 ) - ln ( 2 )}

Solution steps

3 (2^{x + 3}) = 192 (3^{x - 3})

Apply exponent rules

ln (3) + (x + 3) ln (2) = ln (192) + (x - 3) ln (3)

Solve

ln (3) + (x + 3) ln (2) = ln (192) + (x - 3) ln (3) : x = - \frac{ln ( \frac{8}{27} )}{ln ( 3 ) - ln ( 2 )}

x = - \frac{ln ( \frac{8}{27} )}{ln ( 3 ) - ln ( 2 )}

5^{2 x} = 42

5^{2 x} = 25

3 = 1.1 2^{x}

4^{2 v} = 64

What is the answer to 3(2^{x+3})=192(3^{x-3}) ?
The answer to 3(2^{x+3})=192(3^{x-3}) is x=-(ln(8/27))/(ln(3)-ln(2))
Solve for x: 3(2^{x+3})=192(3^{x-3})
The solution is x=-(ln(8/27))/(ln(3)-ln(2))