What is the answer to 27^{2x-3}=9sqrt(3) ?

The answer to 27^{2x-3}=9sqrt(3) is x= 23/12

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27^{2x-3}=9sqrt(3)

2 7^{2 x - 3} = 93

x = \frac{23}{12}

Solution steps

2 7^{2 x - 3} = 93

Apply exponent rules

3 (2 x - 3) = \frac{5}{2}

Solve

3 (2 x - 3) = \frac{5}{2} : x = \frac{23}{12}

x = \frac{23}{12}

2^{x} = (0.25)^{x - 1}

4^{x - 1} = 64

4 + 6^{2 x + 3} = 14

10. 2^{x^{2} - 4} = 320

x, e^{2 x} - 5 e^{x} + 4 = 0

What is the answer to 27^{2x-3}=9sqrt(3) ?
The answer to 27^{2x-3}=9sqrt(3) is x= 23/12
Solve for x: 27^{2x-3}=9sqrt(3)
The solution is x= 23/12