What is the answer to 2^x=20000 ?

The answer to 2^x=20000 is x=(ln(20000))/(ln(2))

Solve for x: 2^x=20000

The solution is x=(ln(20000))/(ln(2))

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2^{x} = 20000

x = \frac{ln ( 20000 )}{ln ( 2 )}

Decimal Notation

x = 14.28771 \dots

Solution steps

2^{x} = 20000

Apply exponent rules

x ln (2) = ln (20000)

Solve

x ln (2) = ln (20000) : x = \frac{ln ( 20000 )}{ln ( 2 )}

x = \frac{ln ( 20000 )}{ln ( 2 )}

e^{x} x^{2} + 4 e^{x} x + 2 e^{x} = 0

3^{2 x} = 9^{\frac{5}{2} x - 3}

x, 8 1^{x} = 3

2 e^{4 x - 2} = 9

10000 = 5000 (1 + 7.5)^{n}

What is the answer to 2^x=20000 ?
The answer to 2^x=20000 is x=(ln(20000))/(ln(2))
Solve for x: 2^x=20000
The solution is x=(ln(20000))/(ln(2))