What are the solutions to the equation 2x^2+288=0 ?

The solutions to the equation 2x^2+288=0 are x=12i,x=-12i

Find the zeros of 2x^2+288=0

The zeros of 2x^2+288=0 are x=12i,x=-12i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 288 = 0

x = 12 i, x = - 12 i

Solution steps

2 x^{2} + 288 = 0

Move

288

to the right side

2 x^{2} = - 288

Divide both sides by

2

x^{2} = - 144

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 144, x = - - 144

- 144 = 12 i

- - 144 = - 12 i

x = 12 i, x = - 12 i

\frac{2 + 3 i}{4 - 2 i}

3 (2 x - 7) = 3

\frac{10}{2}

6 - 4 x = 18

(3 x)^{\frac{3}{4}}

What are the solutions to the equation 2x^2+288=0 ?
The solutions to the equation 2x^2+288=0 are x=12i,x=-12i
Find the zeros of 2x^2+288=0
The zeros of 2x^2+288=0 are x=12i,x=-12i