What is the answer to 10^{3x+7}+8=37 ?

The answer to 10^{3x+7}+8=37 is x=(ln(29)-7ln(10))/(3ln(10))

Solve for x: 10^{3x+7}+8=37

The solution is x=(ln(29)-7ln(10))/(3ln(10))

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1 0^{3 x + 7} + 8 = 37

x = \frac{ln ( 29 ) - 7 ln ( 10 )}{3 ln ( 10 )}

Solution steps

1 0^{3 x + 7} + 8 = 37

Move

8

to the right side

1 0^{3 x + 7} = 29

Apply exponent rules

(3 x + 7) ln (10) = ln (29)

Solve

(3 x + 7) ln (10) = ln (29) : x = \frac{ln ( 29 ) - 7 ln ( 10 )}{3 ln ( 10 )}

x = \frac{ln ( 29 ) - 7 ln ( 10 )}{3 ln ( 10 )}

5^{(- x)} + 7 = 2 x + 4

8^{- 5 a} - 5 = 53

y, x = y e^{y}

m = - 3 (5)^{n + 4} - \frac{1}{2}

3^{x} = 45

What is the answer to 10^{3x+7}+8=37 ?
The answer to 10^{3x+7}+8=37 is x=(ln(29)-7ln(10))/(3ln(10))
Solve for x: 10^{3x+7}+8=37
The solution is x=(ln(29)-7ln(10))/(3ln(10))