What is the answer to 7^{x+4}=10^x ?

The answer to 7^{x+4}=10^x is x=(4ln(7))/(ln(10)-ln(7))

Solve for x: 7^{x+4}=10^x

The solution is x=(4ln(7))/(ln(10)-ln(7))

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7^{x + 4} = 1 0^{x}

x = \frac{4 ln ( 7 )}{ln ( 10 ) - ln ( 7 )}

Decimal Notation

x = 21.82278 \dots

Solution steps

7^{x + 4} = 1 0^{x}

Apply exponent rules

(x + 4) ln (7) = x ln (10)

Solve

(x + 4) ln (7) = x ln (10) : x = \frac{4 ln ( 7 )}{ln ( 10 ) - ln ( 7 )}

x = \frac{4 ln ( 7 )}{ln ( 10 ) - ln ( 7 )}

1.0 7^{n} = 2

e^{(2 x - 1)} = 3

0.4 = 1.0 5^{2 x + 5} - 1

0 = x (2 - x) e^{(- x + 4)}

4 ∣ 5^{x} - 1 ∣ = 5^{x}

What is the answer to 7^{x+4}=10^x ?
The answer to 7^{x+4}=10^x is x=(4ln(7))/(ln(10)-ln(7))
Solve for x: 7^{x+4}=10^x
The solution is x=(4ln(7))/(ln(10)-ln(7))