What is the answer to 3^{2x}-1=15 ?

The answer to 3^{2x}-1=15 is x=(2ln(2))/(ln(3))

Solve for x: 3^{2x}-1=15

The solution is x=(2ln(2))/(ln(3))

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3^{2 x} - 1 = 15

x = \frac{2 ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = 1.26185 \dots

Solution steps

3^{2 x} - 1 = 15

Move

1

to the right side

3^{2 x} = 16

Apply exponent rules

2 x ln (3) = ln (16)

Solve

2 x ln (3) = ln (16) : x = \frac{2 ln ( 2 )}{ln ( 3 )}

x = \frac{2 ln ( 2 )}{ln ( 3 )}

27 (3^{2 x}) - 12 (3^{x}) + 1 = 0

8^{x} = \frac{2 ^{32} - 4 ^{14}}{30}

x = e^{- x} - 2

7^{3 x - 2} = 1

(2 e^{3 x})^{3} = 9

What is the answer to 3^{2x}-1=15 ?
The answer to 3^{2x}-1=15 is x=(2ln(2))/(ln(3))
Solve for x: 3^{2x}-1=15
The solution is x=(2ln(2))/(ln(3))