What are the solutions to the equation 5x^2+21x=-10x-6 ?

The solutions to the equation 5x^2+21x=-10x-6 are x=-1/5 ,x=-6

Find the zeros of 5x^2+21x=-10x-6

The zeros of 5x^2+21x=-10x-6 are x=-1/5 ,x=-6

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5 x^{2} + 21 x = - 10 x - 6

x = - \frac{1}{5}, x = - 6

Decimal Notation

x = - 0.2, x = - 6

Solution steps

5 x^{2} + 21 x = - 10 x - 6

Move

6

to the left side

5 x^{2} + 21 x + 6 = - 10 x

Move

10 x

to the left side

5 x^{2} + 31 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

3 1^{2} - 4 \cdot 5 \cdot 6 = 29

x_{1, 2} = \frac{- 31 \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 31 + 29}{2 \cdot 5}, x_{2} = \frac{- 31 - 29}{2 \cdot 5}

x = \frac{- 31 + 29}{2 \cdot 5} : - \frac{1}{5}

x = \frac{- 31 - 29}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 6

2 x^{2} + 7 x + 4 = 0

x^{2} + 7 x - 17 \leq 1

2 \cdot (x - 5) = 12

x^{6} - 4 x^{4} - 8 x^{4} + 32 x^{2} + 16 x^{2} - 64

What are the solutions to the equation 5x^2+21x=-10x-6 ?
The solutions to the equation 5x^2+21x=-10x-6 are x=-1/5 ,x=-6
Find the zeros of 5x^2+21x=-10x-6
The zeros of 5x^2+21x=-10x-6 are x=-1/5 ,x=-6