What is the answer to 2^{(x+1)}+2^{(x-1)}=20 ?

The answer to 2^{(x+1)}+2^{(x-1)}=20 is x=3

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2^{(x+1)}+2^{(x-1)}=20

2^{(x + 1)} + 2^{(x - 1)} = 20

x = 3

Solution steps

2^{(x + 1)} + 2^{(x - 1)} = 20

Factor

2^{x + 1} + 2^{x - 1} : 5 \cdot 2^{x - 1}

5 \cdot 2^{x - 1} = 20

Divide both sides by

5

2^{x - 1} = 4

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

x, 7^{2 x + y x} = k

e^{x} - e^{- x} = 6

x \cdot e^{x} = - 1

1 0^{a - 3} = 512

(\frac{1}{3})^{2 x - 1} = 27

What is the answer to 2^{(x+1)}+2^{(x-1)}=20 ?
The answer to 2^{(x+1)}+2^{(x-1)}=20 is x=3
Solve for x: 2^{(x+1)}+2^{(x-1)}=20
The solution is x=3