What is the answer to log_{10}(8^x)=-1/3 ?

The answer to log_{10}(8^x)=-1/3 is x=-(ln(10))/(9ln(2))

Solve for x: log_{10}(8^x)=-1/3

The solution is x=-(ln(10))/(9ln(2))

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lo g_{10} (8^{x}) = - \frac{1}{3}

x = - \frac{ln ( 10 )}{9 ln ( 2 )}

Decimal Notation

x = - 0.36910 \dots

Solution steps

lo g_{10} (8^{x}) = - \frac{1}{3}

Rewrite the equation with

8^{x} = u

lo g_{10} (u) = - \frac{1}{3}

Solve

Substitute back

u = 8^{x},

solve for

x

Solve

x = - \frac{ln ( 10 )}{9 ln ( 2 )}

2^{(2 x + 1)} - 5 (2^{x}) + 2 = 0

2^{3 x} + 2^{x} = 10

16 \cdot 4^{v - 2} - 3 = 61

200 = 1000 - 1000 (0.9)^{t}

2 \cdot 1 1^{x} - 4 = 452

What is the answer to log_{10}(8^x)=-1/3 ?
The answer to log_{10}(8^x)=-1/3 is x=-(ln(10))/(9ln(2))
Solve for x: log_{10}(8^x)=-1/3
The solution is x=-(ln(10))/(9ln(2))