What is the answer to 2^{x+1}-2^{x-3}+2^x=23 ?

The answer to 2^{x+1}-2^{x-3}+2^x=23 is x=3

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2^{x+1}-2^{x-3}+2^x=23

2^{x + 1} - 2^{x - 3} + 2^{x} = 23

x = 3

Solution steps

2^{x + 1} - 2^{x - 3} + 2^{x} = 23

Factor

2^{x + 1} - 2^{x - 3} + 2^{x} : 23 \cdot 2^{x - 3}

23 \cdot 2^{x - 3} = 23

Divide both sides by

23

2^{x - 3} = 1

Apply exponent rules

(x - 3) ln (2) = ln (1)

Solve

(x - 3) ln (2) = ln (1) : x = 3

x = 3

4^{x} + 2^{x + 3} = 48

x, e^{x} + 5 e^{- x} = 6

n, 2^{n} = 1000000

3 \cdot 3^{\frac{x}{5}} = 1

2^{3 x} = 128

What is the answer to 2^{x+1}-2^{x-3}+2^x=23 ?
The answer to 2^{x+1}-2^{x-3}+2^x=23 is x=3
Solve for x: 2^{x+1}-2^{x-3}+2^x=23
The solution is x=3