What is the answer to 7^x=2*5^x ?

The answer to 7^x=2*5^x is x=(ln(2))/(ln(7)-ln(5))

Solve for x: 7^x=2*5^x

The solution is x=(ln(2))/(ln(7)-ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{x} = 2 \cdot 5^{x}

x = \frac{ln ( 2 )}{ln ( 7 ) - ln ( 5 )}

Solution steps

7^{x} = 2 \cdot 5^{x}

Apply exponent rules

x ln (7) = ln (2) + x ln (5)

Solve

x ln (7) = ln (2) + x ln (5) : x = \frac{ln ( 2 )}{ln ( 7 ) - ln ( 5 )}

x = \frac{ln ( 2 )}{ln ( 7 ) - ln ( 5 )}

6^{x} = \frac{1}{6}

200 = \frac{500}{1 + e ^{3 - t}}

5^{2 x} + 5^{1 + x} - 6 = 0

4^{5 - 2 x} = 3^{x}

2 (1.08)^{x} = 2.5

What is the answer to 7^x=2*5^x ?
The answer to 7^x=2*5^x is x=(ln(2))/(ln(7)-ln(5))
Solve for x: 7^x=2*5^x
The solution is x=(ln(2))/(ln(7)-ln(5))