What is the answer to 200=4^x ?

The answer to 200=4^x is x=(ln(200))/(2ln(2))

The solution is x=(ln(200))/(2ln(2))

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200=4^x

200 = 4^{x}

x = \frac{ln ( 200 )}{2 ln ( 2 )}

Solution steps

200 = 4^{x}

Apply exponent rules

ln (200) = x ln (4)

Solve

ln (200) = x ln (4) : x = \frac{ln ( 200 )}{2 ln ( 2 )}

x = \frac{ln ( 200 )}{2 ln ( 2 )}

8^{4 x} = \frac{1}{2 2}

200 = 4^{t}

B (t) = 2190 \cdot e^{- 0.3 t}

z, 0 = e^{2 x + 2 y + z}

5^{x + 1} = 625