What is the answer to 81^{x^2-1}=27^{-(7-5x)} ?

The answer to 81^{x^2-1}=27^{-(7-5x)} is No Solution for x\in\mathbb{R}

Solve for x: 81^{x^2-1}=27^{-(7-5x)}

The solution is No Solution for x\in\mathbb{R}

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8 1^{x^{2} - 1} = 2 7^{- (7 - 5 x)}

No Solution for x \in R

Solution steps

8 1^{x^{2} - 1} = 2 7^{- (7 - 5 x)}

Apply exponent rules

4 (x^{2} - 1) = - 3 (7 - 5 x)

Solve

4 (x^{2} - 1) = - 3 (7 - 5 x) :

No Solution for

x \in R

No Solution for x \in R

6 (4^{x}) - 11 (2^{x}) + 4 = 0

6300 = 3130 \cdot 1.0 8^{x}

2^{r} = (\frac{1}{3})^{r - 1}

10 = 2^{\frac{t}{3}}

2 = 1. 2^{x}

What is the answer to 81^{x^2-1}=27^{-(7-5x)} ?
The answer to 81^{x^2-1}=27^{-(7-5x)} is No Solution for x\in\mathbb{R}
Solve for x: 81^{x^2-1}=27^{-(7-5x)}
The solution is No Solution for x\in\mathbb{R}