What is the answer to 2^{x-3}=5 ?

The answer to 2^{x-3}=5 is x=(ln(5))/(ln(2))+3

Solve for x: 2^{x-3}=5

The solution is x=(ln(5))/(ln(2))+3

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2^{x - 3} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} + 3

Decimal Notation

x = 5.32192 \dots

Solution steps

2^{x - 3} = 5

Apply exponent rules

(x - 3) ln (2) = ln (5)

Solve

(x - 3) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} + 3

x = \frac{ln ( 5 )}{ln ( 2 )} + 3

9 (5^{x}) = 8^{x + 4}

5^{6 x + 1} - 6 \cdot 5^{3 x} + 1 = 0

(2)^{x} = 16

3^{x} - 3^{1 - x} = 2

e^{x} = e^{4 - x}

What is the answer to 2^{x-3}=5 ?
The answer to 2^{x-3}=5 is x=(ln(5))/(ln(2))+3
Solve for x: 2^{x-3}=5
The solution is x=(ln(5))/(ln(2))+3