What is the answer to 64^{x^2}=16^{x^2+2x} ?

The answer to 64^{x^2}=16^{x^2+2x} is x=0,x=4

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64^{x^2}=16^{x^2+2x}

6 4^{x^{2}} = 1 6^{x^{2} + 2 x}

x = 0, x = 4

Solution steps

6 4^{x^{2}} = 1 6^{x^{2} + 2 x}

Apply exponent rules

3 x^{2} = 2 (x^{2} + 2 x)

Solve

3 x^{2} = 2 (x^{2} + 2 x) : x = 0, x = 4

x = 0, x = 4

\frac{5 ^{2 - x}}{5 ^{x}} = 5^{16}

2^{4 x - x^{2}} = 8

\frac{2 ^{x - 3}}{4 ^{10}} = 8^{3}

1 0^{x} = 0.5

1 0^{x} = 0.2

What is the answer to 64^{x^2}=16^{x^2+2x} ?
The answer to 64^{x^2}=16^{x^2+2x} is x=0,x=4
Solve for x: 64^{x^2}=16^{x^2+2x}
The solution is x=0,x=4