What is the answer to 729^{x-5}=(3^2)^{1-x} ?

The answer to 729^{x-5}=(3^2)^{1-x} is x=4

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729^{x-5}=(3^2)^{1-x}

72 9^{x - 5} = (3^{2})^{1 - x}

x = 4

Solution steps

72 9^{x - 5} = (3^{2})^{1 - x}

Apply exponent rules

6 (x - 5) = 2 (1 - x)

Solve

6 (x - 5) = 2 (1 - x) : x = 4

x = 4

e^{x} + 3 x = 0

5^{n} = 1901

e^{x + 7} = 12

w, 2 z = e^{w} - e^{- w}

\frac{60}{1 + e ^{- x}} = 4

What is the answer to 729^{x-5}=(3^2)^{1-x} ?
The answer to 729^{x-5}=(3^2)^{1-x} is x=4
Solve for x: 729^{x-5}=(3^2)^{1-x}
The solution is x=4