What is the answer to 3^{2x+3}=27^{4x-4} ?

The answer to 3^{2x+3}=27^{4x-4} is x= 3/2

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3^{2x+3}=27^{4x-4}

3^{2 x + 3} = 2 7^{4 x - 4}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

3^{2 x + 3} = 2 7^{4 x - 4}

Apply exponent rules

2 x + 3 = 3 (4 x - 4)

Solve

2 x + 3 = 3 (4 x - 4) : x = \frac{3}{2}

x = \frac{3}{2}

e^{x} + e^{2} x = e^{3} x

4^{x + 1} - 5^{x + 1} = (0.8) (4^{x})

1.73 = 3^{x}

5^{- 3 x - 1} = 25

x^{l o g_{10} (x)} = 100

What is the answer to 3^{2x+3}=27^{4x-4} ?
The answer to 3^{2x+3}=27^{4x-4} is x= 3/2
Solve for x: 3^{2x+3}=27^{4x-4}
The solution is x= 3/2