What is the answer to 2^{2x}=5^{1-2x} ?

The answer to 2^{2x}=5^{1-2x} is x=(ln(5))/(2ln(10))

Solve for x: 2^{2x}=5^{1-2x}

The solution is x=(ln(5))/(2ln(10))

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2^{2 x} = 5^{1 - 2 x}

x = \frac{ln ( 5 )}{2 ln ( 10 )}

Solution steps

2^{2 x} = 5^{1 - 2 x}

Apply exponent rules

2 x ln (2) = (1 - 2 x) ln (5)

Solve

2 x ln (2) = (1 - 2 x) ln (5) : x = \frac{ln ( 5 )}{2 ln ( 10 )}

x = \frac{ln ( 5 )}{2 ln ( 10 )}

2 \cdot 3^{x} = 5^{2 x}

3^{x} + 3^{x - 1} = 4

\frac{( e ^{x} )}{1 - x} = 0

0. 8^{x} = \frac{5}{4}

x, y = e^{x} (y - 2)

What is the answer to 2^{2x}=5^{1-2x} ?
The answer to 2^{2x}=5^{1-2x} is x=(ln(5))/(2ln(10))
Solve for x: 2^{2x}=5^{1-2x}
The solution is x=(ln(5))/(2ln(10))