What is the answer to 1/3 3^{4x+2}-3^{2x-5}=0 ?

The answer to 1/3 3^{4x+2}-3^{2x-5}=0 is x=-3

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1/3 3^{4x+2}-3^{2x-5}=0

\frac{1}{3} 3^{4 x + 2} - 3^{2 x - 5} = 0

x = - 3

Solution steps

\frac{1}{3} \cdot 3^{4 x + 2} - 3^{2 x - 5} = 0

Add

3^{2 x - 5}

to both sides

\frac{1}{3} \cdot 3^{4 x + 2} - 3^{2 x - 5} + 3^{2 x - 5} = 0 + 3^{2 x - 5}

Simplify

\frac{1}{3} \cdot 3^{4 x + 2} = 3^{2 x - 5}

Apply exponent rules

4 x + 1 = 2 x - 5

Solve

4 x + 1 = 2 x - 5 : x = - 3

x = - 3

9^{x + 1} - 3^{x + 3} - 3^{x} + 3 = 0

\frac{70}{1 + e ^{- x}} = 3

9 \cdot 9 = 3^{x}

4^{x} + 2^{x} = 20

What is the answer to 1/3 3^{4x+2}-3^{2x-5}=0 ?
The answer to 1/3 3^{4x+2}-3^{2x-5}=0 is x=-3
Solve for x: 1/3 3^{4x+2}-3^{2x-5}=0
The solution is x=-3