What is the answer to 5(7^{x-2})=8 ?

The answer to 5(7^{x-2})=8 is x=(ln(8/5))/(ln(7))+2

Solve for x: 5(7^{x-2})=8

The solution is x=(ln(8/5))/(ln(7))+2

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5 (7^{x - 2}) = 8

x = \frac{ln ( \frac{8}{5} )}{ln ( 7 )} + 2

Solution steps

5 (7^{x - 2}) = 8

Divide both sides by

5

7^{x - 2} = \frac{8}{5}

Apply exponent rules

(x - 2) ln (7) = ln (\frac{8}{5})

Solve

(x - 2) ln (7) = ln (\frac{8}{5}) : x = \frac{ln ( \frac{8}{5} )}{ln ( 7 )} + 2

x = \frac{ln ( \frac{8}{5} )}{ln ( 7 )} + 2

\frac{3 ^{- 1}}{3 ^{4}} = 3^{a}

2^{k} + 2^{k} = 2^{k + 1}

8 = 4^{- x + 4}

4 9^{x - 1} = 77

4^{3 - x} = \frac{1}{16}

What is the answer to 5(7^{x-2})=8 ?
The answer to 5(7^{x-2})=8 is x=(ln(8/5))/(ln(7))+2
Solve for x: 5(7^{x-2})=8
The solution is x=(ln(8/5))/(ln(7))+2