What are the solutions to the equation v^2+8v+15=0 ?

The solutions to the equation v^2+8v+15=0 are v=-3,v=-5

Find the zeros of v^2+8v+15=0

The zeros of v^2+8v+15=0 are v=-3,v=-5

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v^{2} + 8 v + 15 = 0

v = - 3, v = - 5

Solution steps

v^{2} + 8 v + 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

v_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 8 + 2}{2 \cdot 1}, v_{2} = \frac{- 8 - 2}{2 \cdot 1}

v = \frac{- 8 + 2}{2 \cdot 1} : - 3

v = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

v = - 3, v = - 5

t + 2 < 13

e^{x} = 0

6 x^{2} + 12 x = - 2

∣ w - 4 ∣ > 3

\frac{2}{x} \leq \frac{1}{x + 6}

What are the solutions to the equation v^2+8v+15=0 ?
The solutions to the equation v^2+8v+15=0 are v=-3,v=-5
Find the zeros of v^2+8v+15=0
The zeros of v^2+8v+15=0 are v=-3,v=-5