What is the answer to 2^{2x+18}=3^{x-12} ?

The answer to 2^{2x+18}=3^{x-12} is x=(-12ln(3)-18ln(2))/(2ln(2)-ln(3))

Solve for x: 2^{2x+18}=3^{x-12}

The solution is x=(-12ln(3)-18ln(2))/(2ln(2)-ln(3))

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2^{2 x + 18} = 3^{x - 12}

x = \frac{- 12 ln ( 3 ) - 18 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

Solution steps

2^{2 x + 18} = 3^{x - 12}

Apply exponent rules

(2 x + 18) ln (2) = (x - 12) ln (3)

Solve

(2 x + 18) ln (2) = (x - 12) ln (3) : x = \frac{- 12 ln ( 3 ) - 18 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

x = \frac{- 12 ln ( 3 ) - 18 ln ( 2 )}{2 ln ( 2 ) - ln ( 3 )}

e^{x} = 17.8

x e^{x} - e^{x} = 0

6 = e^{x}

m, 9^{m} = 3^{n}

8^{3 - x} = 2^{3 - 2 x}

What is the answer to 2^{2x+18}=3^{x-12} ?
The answer to 2^{2x+18}=3^{x-12} is x=(-12ln(3)-18ln(2))/(2ln(2)-ln(3))
Solve for x: 2^{2x+18}=3^{x-12}
The solution is x=(-12ln(3)-18ln(2))/(2ln(2)-ln(3))