What is the answer to 2^{2x+1}+4^{x-1}=9 ?

The answer to 2^{2x+1}+4^{x-1}=9 is x=1

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2^{2x+1}+4^{x-1}=9

2^{2 x + 1} + 4^{x - 1} = 9

x = 1

Solution steps

2^{2 x + 1} + 4^{x - 1} = 9

Apply exponent rules

2 x = 2

Solve

2 x = 2 : x = 1

x = 1

t, e^{t} = x^{2}

8^{x - 2} = 6^{3 x}

5 (3^{x}) - 40 (3^{- x}) = 17

x, e^{\frac{2 x}{5}} = 25

e^{x} - 2 x = 0

What is the answer to 2^{2x+1}+4^{x-1}=9 ?
The answer to 2^{2x+1}+4^{x-1}=9 is x=1
Solve for x: 2^{2x+1}+4^{x-1}=9
The solution is x=1