What is the answer to 2^{x+7}*4^{x-1}=8^{2x+3} ?

The answer to 2^{x+7}*4^{x-1}=8^{2x+3} is x=-4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x+7}*4^{x-1}=8^{2x+3}

2^{x + 7} \cdot 4^{x - 1} = 8^{2 x + 3}

x = - \frac{4}{3}

Decimal Notation

x = - 1.33333 \dots

Solution steps

2^{x + 7} \cdot 4^{x - 1} = 8^{2 x + 3}

Apply exponent rules

x - 1 + 8 + 2 (x - 1) = 3 (2 x + 3)

Solve

x - 1 + 8 + 2 (x - 1) = 3 (2 x + 3) : x = - \frac{4}{3}

x = - \frac{4}{3}

3000 = 100 e^{n}

6^{2 x - 7} = 216

3^{x^{2} - 4 x + 1} = \frac{1}{81}

e^{x} = 7 - 12 e^{- x}

((\frac{1}{2})^{x})^{1} = 2

What is the answer to 2^{x+7}*4^{x-1}=8^{2x+3} ?
The answer to 2^{x+7}*4^{x-1}=8^{2x+3} is x=-4/3
Solve for x: 2^{x+7}*4^{x-1}=8^{2x+3}
The solution is x=-4/3