What are the solutions to the equation x^2-11x+3=5 ?

The solutions to the equation x^2-11x+3=5 are x=(11+sqrt(129))/2 ,x=(11-sqrt(129))/2

Find the zeros of x^2-11x+3=5

The zeros of x^2-11x+3=5 are x=(11+sqrt(129))/2 ,x=(11-sqrt(129))/2

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x^{2} - 11 x + 3 = 5

x = \frac{11 + 129}{2}, x = \frac{11 - 129}{2}

Decimal Notation

x = 11.17890 \dots, x = - 0.17890 \dots

Solution steps

x^{2} - 11 x + 3 = 5

Move

5

to the left side

x^{2} - 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 2) = 129

x_{1, 2} = \frac{- ( - 11 ) \pm 129}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 129}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 129}{2 \cdot 1}

x = \frac{- ( - 11 ) + 129}{2 \cdot 1} : \frac{11 + 129}{2}

x = \frac{- ( - 11 ) - 129}{2 \cdot 1} : \frac{11 - 129}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 129}{2}, x = \frac{11 - 129}{2}

(1 6^{\frac{1}{4}})^{3}

x^{2} - 47 = 0

75

k^{2} - 31 - 2 k = - 6 - 3 k^{2} - 2 k

a^{5} - a^{3} b^{2} - a^{2} b^{3} + b^{5}

What are the solutions to the equation x^2-11x+3=5 ?
The solutions to the equation x^2-11x+3=5 are x=(11+sqrt(129))/2 ,x=(11-sqrt(129))/2
Find the zeros of x^2-11x+3=5
The zeros of x^2-11x+3=5 are x=(11+sqrt(129))/2 ,x=(11-sqrt(129))/2