What is the answer to sqrt(2^{2x-1)}=16^{x-2} ?

The answer to sqrt(2^{2x-1)}=16^{x-2} is x= 5/2

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sqrt(2^{2x-1)}=16^{x-2}

2^{2 x - 1} = 1 6^{x - 2}

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

2^{2 x - 1} = 1 6^{x - 2}

Apply exponent rules

(2 x - 1) \frac{1}{2} = 4 (x - 2)

Solve

(2 x - 1) \frac{1}{2} = 4 (x - 2) : x = \frac{5}{2}

x = \frac{5}{2}

5 c e^{c x} = 2 e^{c x}

4^{x + 1} + 4^{x + 2} = 1280

3^{x + 2} = \frac{1}{81}

3^{2 x} = 7^{3 x - 1}

9 \cdot 5^{- x} + 5^{x} = 10

What is the answer to sqrt(2^{2x-1)}=16^{x-2} ?
The answer to sqrt(2^{2x-1)}=16^{x-2} is x= 5/2
Solve for x: sqrt(2^{2x-1)}=16^{x-2}
The solution is x= 5/2