What is the answer to 5^{x+1}=6 ?

The answer to 5^{x+1}=6 is x=(ln(6))/(ln(5))-1

Solve for x: 5^{x+1}=6

The solution is x=(ln(6))/(ln(5))-1

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5^{x + 1} = 6

x = \frac{ln ( 6 )}{ln ( 5 )} - 1

Decimal Notation

x = 0.11328 \dots

Solution steps

5^{x + 1} = 6

Apply exponent rules

(x + 1) ln (5) = ln (6)

Solve

(x + 1) ln (5) = ln (6) : x = \frac{ln ( 6 )}{ln ( 5 )} - 1

x = \frac{ln ( 6 )}{ln ( 5 )} - 1

5^{x + 1} = 5

5 e^{x^{2} - 6 x - 9} = 1

15 = 12 e^{x - 2}

3^{x + 2} = 2^{1 - x}

e^{x} = x^{10}

What is the answer to 5^{x+1}=6 ?
The answer to 5^{x+1}=6 is x=(ln(6))/(ln(5))-1
Solve for x: 5^{x+1}=6
The solution is x=(ln(6))/(ln(5))-1