What is the answer to 7^{6x+7}=2 ?

The answer to 7^{6x+7}=2 is x=(ln(2)-7ln(7))/(6ln(7))

Solve for x: 7^{6x+7}=2

The solution is x=(ln(2)-7ln(7))/(6ln(7))

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7^{6 x + 7} = 2

x = \frac{ln ( 2 ) - 7 ln ( 7 )}{6 ln ( 7 )}

Decimal Notation

x = - 1.10729 \dots

Solution steps

7^{6 x + 7} = 2

Apply exponent rules

(6 x + 7) ln (7) = ln (2)

Solve

(6 x + 7) ln (7) = ln (2) : x = \frac{ln ( 2 ) - 7 ln ( 7 )}{6 ln ( 7 )}

x = \frac{ln ( 2 ) - 7 ln ( 7 )}{6 ln ( 7 )}

x + 5 = 5^{x}

2^{3 x - 1} = \frac{1}{2}

2 e^{2 x} + 5 e^{x} - 3 = 0

x, x y = e^{4 x - y} - 1

(\frac{2}{3})^{x} = \frac{4}{9}

What is the answer to 7^{6x+7}=2 ?
The answer to 7^{6x+7}=2 is x=(ln(2)-7ln(7))/(6ln(7))
Solve for x: 7^{6x+7}=2
The solution is x=(ln(2)-7ln(7))/(6ln(7))