What is the answer to 3^{x-2}=7 ?

The answer to 3^{x-2}=7 is x=(ln(7))/(ln(3))+2

Solve for x: 3^{x-2}=7

The solution is x=(ln(7))/(ln(3))+2

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3^{x - 2} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} + 2

Decimal Notation

x = 3.77124 \dots

Solution steps

3^{x - 2} = 7

Apply exponent rules

(x - 2) ln (3) = ln (7)

Solve

(x - 2) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} + 2

x = \frac{ln ( 7 )}{ln ( 3 )} + 2

(- 2)^{x} = - 32

4.7 = 3000000 (1 + 0.23)^{n}

1 - e^{2 x} = 0

\frac{1}{4} = 2^{n}

1 + 1. 2^{x} = 1. 2^{2 x}

What is the answer to 3^{x-2}=7 ?
The answer to 3^{x-2}=7 is x=(ln(7))/(ln(3))+2
Solve for x: 3^{x-2}=7
The solution is x=(ln(7))/(ln(3))+2