What is the answer to 2^{x+4}=5 ?

The answer to 2^{x+4}=5 is x=(ln(5))/(ln(2))-4

Solve for x: 2^{x+4}=5

The solution is x=(ln(5))/(ln(2))-4

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2^{x + 4} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} - 4

Decimal Notation

x = - 1.67807 \dots

Solution steps

2^{x + 4} = 5

Apply exponent rules

(x + 4) ln (2) = ln (5)

Solve

(x + 4) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} - 4

x = \frac{ln ( 5 )}{ln ( 2 )} - 4

2^{3 x} = 6^{x + 2}

5^{2 x - 13} = 25

\frac{2 e ^{x}}{4} = 9

17.3 = e^{1.1 x}

e^{2 x + 3} = 1

What is the answer to 2^{x+4}=5 ?
The answer to 2^{x+4}=5 is x=(ln(5))/(ln(2))-4
Solve for x: 2^{x+4}=5
The solution is x=(ln(5))/(ln(2))-4